X^2-(11/3)*x+(10/3)=0

Solution for X^2-(11/3)*x+(10/3)=0 equation:

X^2-(11/3)*X+(10/3)=0


Domain of the equation: 3)*X!=0

X!=0/1

X!=0

X∈R


We add all the numbers together, and all the variables

X^2-(+11/3)*X+(+10/3)=0

We multiply parentheses

X^2-11X^2+(+10/3)=0

We get rid of parentheses

X^2-11X^2+10/3=0

We multiply all the terms by the denominator


X^2*3-11X^2*3+10=0

Wy multiply elements

3X^2-33X^2+10=0

We add all the numbers together, and all the variables

-30X^2+10=0

a = -30; b = 0; c = +10;
Δ = b2-4ac
Δ = 02-4·(-30)·10
Δ = 1200
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{1200}=\sqrt{400*3}=\sqrt{400}*\sqrt{3}=20\sqrt{3}$
$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-20\sqrt{3}}{2*-30}=\frac{0-20\sqrt{3}}{-60}
=-\frac{20\sqrt{3}}{-60}
=-\frac{\sqrt{3}}{-3}
$
$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+20\sqrt{3}}{2*-30}=\frac{0+20\sqrt{3}}{-60}
=\frac{20\sqrt{3}}{-60}
=\frac{\sqrt{3}}{-3}
$